<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: I need help on Probability and Statistics?</title>
	<atom:link href="http://www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html/feed" rel="self" type="application/rss+xml" />
	<link>http://www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html</link>
	<description>car insurance</description>
	<lastBuildDate>Tue, 17 Aug 2010 18:12:21 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.0</generator>
	<item>
		<title>By: kitten</title>
		<link>http://www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html/comment-page-1#comment-3998</link>
		<dc:creator>kitten</dc:creator>
		<pubDate>Thu, 11 Mar 2010 05:39:29 +0000</pubDate>
		<guid isPermaLink="false">http://www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html#comment-3998</guid>
		<description>P(L) = .6 P(M) = .3 P(H) = .1
P(A&#124;L) = .01 P(A&#124;M) = .05 P(A&#124;H) = .09
Using the formula of total probability,
P(A) = P(A&#124;L)P(L) + P(A&#124;M)P(M) + P(A&#124;H)P(H)
= (.01)(.6) + (.05)(.3) + (.09)(.1)
= .03</description>
		<content:encoded><![CDATA[<p>P(L) = .6 P(M) = .3 P(H) = .1<br />
P(A|L) = .01 P(A|M) = .05 P(A|H) = .09<br />
Using the formula of total probability,<br />
P(A) = P(A|L)P(L) + P(A|M)P(M) + P(A|H)P(H)<br />
= (.01)(.6) + (.05)(.3) + (.09)(.1)<br />
= .03</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: John S</title>
		<link>http://www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html/comment-page-1#comment-3997</link>
		<dc:creator>John S</dc:creator>
		<pubDate>Thu, 11 Mar 2010 05:01:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html#comment-3997</guid>
		<description>60% * 1% + 30% * 5% + 9% * 10% =
(.6 * .01) + (.3 * .05) + (.1 * .09) =
.006 + 0.015 + 0.009 = .03 * 100 = 3%</description>
		<content:encoded><![CDATA[<p>60% * 1% + 30% * 5% + 9% * 10% =<br />
(.6 * .01) + (.3 * .05) + (.1 * .09) =<br />
.006 + 0.015 + 0.009 = .03 * 100 = 3%</p>
]]></content:encoded>
	</item>
</channel>
</rss>
<!-- This Quick Cache file was built for (  www.thecarinsurance.net/i-need-help-on-probability-and-statistics.html/feed ) in 0.53145 seconds, on Sep 9th, 2010 at 6:40 am UTC. -->
<!-- This Quick Cache file will automatically expire ( and be re-built automatically ) on Sep 9th, 2010 at 7:40 am UTC -->